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\newtheorem{case}[theorem]{Case}
\newtheorem{claim}[theorem]{Claim}
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\begin{document}
La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{8}{5}x+\dfrac{9}{7}=\dfrac{11}%
{10}x+2$ es:\medskip\newline\qquad a)\textbf{\ }$x=\dfrac{10}{7}$\qquad b)
$x=-\dfrac{46}{7}$\qquad c) $x=-\dfrac{10}{7}$\qquad d) $x=\dfrac{230}{189}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{1}{5}x+\dfrac{9}{7}=\dfrac{11}%
{8}x+3$ es:\medskip\newline\qquad a)\textbf{\ }$x=-\dfrac{480}{329}$\qquad b)
$x=\dfrac{480}{329}$\qquad c) $x=-\dfrac{329}{480}$\qquad d) $x=\dfrac
{329}{480}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{2}{5}x+\dfrac{1}{4}=\dfrac{11}%
{3}x+2$ es:\newline\qquad a)\textbf{\ }$x=-\dfrac{15}{28}$\qquad b)
$x=\dfrac{15}{28}$\qquad c) $x=-\dfrac{5}{28}$\qquad d) $x=-\dfrac{16}{28}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{1}{5}x+\dfrac{1}{7}=\dfrac{3}%
{8}x+1$ es:$\medskip$\newline$\qquad a)\mathbf{\ }x=-\dfrac{240}{49}\qquad
b)x=\dfrac{240}{49}\qquad c)x=-\dfrac{230}{49}\qquad d)x=-\dfrac{240}{39}$

La soluci\'{o}n de la ecuaci\'{o}n $-\dfrac{2}{5}x+\dfrac{3}{16}=\dfrac{2}%
{3}x+5$ es:\medskip\newline\qquad a)\textbf{\ }$x=-\dfrac{1155}{256}$\qquad b)
$x=\dfrac{1155}{256}$\qquad c) $x=-\dfrac{115}{256}$\qquad d) $x=-\dfrac
{1114}{256}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{5}{6}x+\dfrac{10}{3}=\dfrac{8}%
{12}x-3$ es:\bigskip\newline\qquad a) \textbf{\ }$x=-38$\qquad b)
$x=\dfrac{240}{191}$\qquad c) $x=\dfrac{12}{5}$\qquad d) $x=-\dfrac{12}{5}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{7}{5}x+\dfrac{5}{2}=\dfrac{9}%
{10}x+2$ es: \bigskip\newline\qquad a) $x=-1$\qquad b) $x=-\dfrac{150}{7}%
$\qquad c) \textbf{\ }$x=\dfrac{150}{7}$\qquad d) $x=1$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{5}{4}x+\dfrac{7}{5}=\dfrac{11}%
{8}x+1\bigskip$\newline\qquad a) $x=\dfrac{16}{5}$\qquad b) $x=\dfrac{45}{56}%
$\qquad c) \textbf{\ }$x=\dfrac{7}{5}$\qquad d) $x=-\dfrac{16}{5}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{2}{3}x+\dfrac{7}{3}=\dfrac{11}%
{9}x+2$, Solution is: $\frac{3}{5}$ es: \bigskip\newline\qquad\medskip a)
$x=\dfrac{3}{5}$\qquad b) $x=\dfrac{81}{75}$\qquad c) \textbf{\ }$x=\dfrac
{12}{5}$\qquad d) $x=-\dfrac{3}{5}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{4}{5}x-\dfrac{7}{2}=\dfrac{13}%
{15}x-1$ \bigskip\newline\qquad a) $x=-\dfrac{75}{2}$\qquad b) $x=\dfrac
{125}{4}$\qquad c) $x=\dfrac{75}{2}$\textbf{\ }\qquad d) $x=-\dfrac{35}{4}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{5}{7}x-\dfrac{3}{5}=\dfrac{11}%
{14}x+3$ \bigskip\newline\qquad a) $x=-\dfrac{252}{5}$\qquad b) $x=\dfrac
{5}{252}$\qquad c) \textbf{\ }$x=\dfrac{252}{5}$\qquad d) $x=-\dfrac{5}{252}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{3}{5}x-\dfrac{2}{3}=\dfrac{7}%
{10}x+1\bigskip$\newline\qquad a) $x=-\dfrac{50}{3}$\qquad b) $x=\dfrac{50}%
{3}$\qquad c) \textbf{\ }$x=\dfrac{3}{50}$\qquad d) $x=-1$\bigskip

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{2}{3}x-\dfrac{5}{9}=\dfrac{5}%
{6}x-2$ \bigskip\newline\qquad a) $x=\dfrac{26}{3}$\qquad b) $x=-\dfrac{26}%
{3}$\qquad c) \textbf{\ }$x=\dfrac{3}{26}$\qquad d) $x=-\dfrac{3}{26}$

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{4}{5}x-\dfrac{2}{3}=\dfrac{9}%
{10}x-2$ es: \bigskip\newline\qquad a)\textbf{\ }$x=\dfrac{40}{3}$ \qquad b)
$x=\dfrac{3}{40}$\qquad c) $x=-\dfrac{40}{3}$\qquad d) $x=-\dfrac{120}{17}%
$\bigskip

La soluci\'{o}n de la ecuaci\'{o}n $\dfrac{5}{4}x-\dfrac{1}{5}=\dfrac{9}%
{8}x+3$, es:\bigskip\ \newline\qquad a) $x=\dfrac{128}{5}$\qquad b)
$x=-\dfrac{5}{128}$\qquad c) \textbf{\ }$x=\dfrac{5}{128}$\qquad d)
$x=-\dfrac{128}{5}$


\end{document}